9p^2+6p+1=16

Solution for 9p^2+6p+1=16 equation:

9p^2+6p+1=16

We move all terms to the left:

9p^2+6p+1-(16)=0

We add all the numbers together, and all the variables

9p^2+6p-15=0

a = 9; b = 6; c = -15;
Δ = b2-4ac
Δ = 62-4·9·(-15)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-24}{2*9}=\frac{-30}{18}
=-1+2/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+24}{2*9}=\frac{18}{18}
=1
$